This question was previously asked in

DSSSB Junior Steno Previous Paper (Held On : 23 April 2021 Shift 2)

Option 2 : 93

**Given:**

Ratio of mixture = 3 : 2

The diluted percentage of milk is 5% and 10%

**Formula used:**

Percentage change = [(original value - new value)/original value] × 100

Percentage change = (concentration value/total value) × 100

**Calculation:**

Ratio of mixture = 3 : 2

Diluted percentage of milk is 5% and 10%

Let the values of mixture be 3a and 2a

Total mixture = 5a

Concentration of first mixture = 3a - 5% of 3a

⇒ (60a - 3a)/20 = 57a/20

Concentration of second mixture = 2a - 10% of 2a

⇒ (20a - 2a)/10 = 18a/10

Percentage change = (New concentration mixture/Total mixture) × 100

Percentage change = [(57a/20 + 18a/10)/5a] × 100

⇒ Percentage change = (93a × 100)/(20 × 5a) = 93

**∴ The concentration of milk in the resultant mixture is 93%.**